R. David Murray added the comment:
>>> p.add_argument('-a', action="append", default=None)
>>> p.parse_args([])
Namespace(a=None)
>>> p.parse_args(['-a', '1', '-a', '2'])
Namespace(a=['1', '2'])
So there's a logical correspondence there (repeated option vs multiple values,
each producing a list).
I'm not sure what you mean by the difference between options and positionals.
I note that you can use nargs with an optional, and in that case the default
works, which is even more unfortunate than the difference with 'append'. But
if you can articulate a logical difference between optionals and positional
here, maybe we can make it look reasonable :)
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue16878>
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