John O'Connor added the comment:
Looking at the implementation (rather quickly)[1]. I'm wondering if there is a
reason why the appendleft(pop()) loop is required. It would seem the best way
would be to determine the new head link, make the previous link the new end
link and concatenate the two chains (by just swapping some pointers).
[1].
http://hg.python.org/cpython/file/a4292889e942/Modules/_collectionsmodule.c#l429
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<http://bugs.python.org/issue16398>
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