Wouter Bolsterlee added the comment: An additional speedup would be to add a "if len(h) == 1" check inside the while loop, and just yield from the remaining iterator if a single iterable remains. This would also speed up merges with multiple inputs, as it doesn't do the whole heapreplace() loop for the last remaining iterable. Example: merge([], [], [], range(100000). This would involve some more refactoring inside the function though, since the current implementation only stores the .next() function for each iterable.
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