Mateusz Loskot added the comment: I have just tested Windows GUI application built against Python 3.2.1 with is_valid_fd patch according to http://hg.python.org/cpython/rev/f15943505db0/
All built using VS2012. Again, I can confirm that is_valid_fd does NOT solve the problem. Here is extract of execution flow in initstdio function: 1. fd = 0, despite it is GUI app, see https://connect.microsoft.com/VisualStudio/feedback/details/785119/ fd = fileno(stdin); 2. is_valid_fd will return __true__, so it moves to calling create_stdio() if (!is_valid_fd(fd)) { ... } else { std = create_stdio(iomod, fd, 0, "<stdin>", encoding, errors); if (std == NULL) goto error; } 3. The create_stdio() call fails though, causing error followed by abort Still, the only solution that solves this problem in Windows GUI applications buitl using VS2012 is to use check_fd() function to check fd, instead of is_valid_fd(). The check_fd() is more reliable as it will return -1 due to errno == EBADF. My previous attempt to analyse _PyVerify_fd() is not relevant for the problem, let's forget it. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue17797> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
