Guido van Rossum added the comment: id(a.__abs__) == id(a.__abs__)
has a completely different explanation -- it so happens that the first instantiation of a.__abs__ is freed after id() is called on it and the second instantiation happens to reuse that same memory block. ---------- nosy: +gvanrossum __________________________________ Tracker <[EMAIL PROTECTED]> <http://bugs.python.org/issue1981> __________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
