New submission from Martin Panter:
The documentation says that guess_type() takes a URL, but:
>>> mimetypes.guess_type("http://example.com";)
('application/x-msdownload', None)
I suspect the MS download is a reference to *.com files (like DOS's
command.com). My current workaround is to strip out the host name from the URL,
since I cannot imagine it would be useful for determining the content type. I
am also stripping the fragment part. An argument could probably be made for
stripping the “;parameters” and “?query” parts as well.
>>> # Workaround for mimetypes.guess_type("//example.com")
... # interpreting host name as file name
... url = urlparse("http://example.com";)
>>> url = net.url_replace(url, netloc="", fragment="")
>>> url
'http://'
>>> mimetypes.guess_type(url, strict=False)
(None, None)
----------
components: Library (Lib)
messages: 226467
nosy: vadmium
priority: normal
severity: normal
status: open
title: mimetypes.guess_type("//example.com") misinterprets host name as file
name
type: behavior
versions: Python 3.4
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Python tracker <[email protected]>
<http://bugs.python.org/issue22347>
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