Guido van Rossum added the comment:
@Joshua: Re: f(x: y for x, y in z)
I don't think that follows at all.
We support f(**d) now, but if d == {'a': 1, 'b': 2}, it is equivalent to f(a=1,
b=2), not f(a: 1, b: 2).
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<http://bugs.python.org/issue2292>
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