Serhiy Storchaka added the comment:
It may be written simpler:
d = defaultdict(factory)
for i in constants:
d[i]
or
d = defaultdict(factory, {i: factory() for i in constants})
I'm inclined to reject this proposition. It serves very special use case.
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nosy: +serhiy.storchaka
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<http://bugs.python.org/issue23372>
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