Gregory P. Smith added the comment: I think this was just overlooked when implementing argparse. Most code out there is likely to get the executable name using:
os.path.basename(sys.argv[0]) Which is going to do exactly what you are seeing here when sys.argv[0] ends with a /. feel free to submit a patch. perhaps as simple as this? os.path.basename(sys.argv[0].rstrip(os.path.sep)) But I'd expect a bunch of other code out there to have the same problem. ---------- nosy: +gregory.p.smith _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue23994> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
