Mark Dickinson <[EMAIL PROTECTED]> added the comment: > Hmm, AFAIKT there is always at least one non-residue between 1 and p > and therefore you can just write > > for i in itertools.count(1): > if (i_is_a_nonresidue_modulo_p): > break > > maybe with an additional check for p > 1.
Sure. It's just uglier that way. :-) And I feel it would be mildly annoying not to be able to use the obvious tool for the job, for subtle reasons. It's also a potential source of bugs: one might write such code using range and only discover later that it fails unexpectedly for large inputs. These really aren't serious objections---just mild preferences. I'll stop being disruptive now :) __________________________________ Tracker <[EMAIL PROTECTED]> <http://bugs.python.org/issue2690> __________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
