New submission from Joshua Landau:
This is valid:
℘· = 1
print(℘·)
#>>> 1
But this gives an error token:
from io import BytesIO
from tokenize import tokenize
stream = BytesIO("℘·".encode("utf-8"))
print(*tokenize(stream.read), sep="\n")
#>>> TokenInfo(type=56 (ENCODING), string='utf-8', start=(0, 0), end=(0,
0), line='')
#>>> TokenInfo(type=53 (ERRORTOKEN), string='℘', start=(1, 0), end=(1, 1),
line='℘·')
#>>> TokenInfo(type=53 (ERRORTOKEN), string='·', start=(1, 1), end=(1, 2),
line='℘·')
#>>> TokenInfo(type=0 (ENDMARKER), string='', start=(2, 0), end=(2, 0),
line='')
This is a continuation of http://bugs.python.org/issue9712. I'm not able to
reopen the issue, so I thought I should report it anew.
It is tokenize that is wrong - Other_ID_Start and Other_ID_Continue are
documented to be valid:
https://docs.python.org/3.5/reference/lexical_analysis.html#identifiers
----------
components: Library (Lib)
messages: 243188
nosy: Joshua.Landau
priority: normal
severity: normal
status: open
title: tokenize yield an ERRORTOKEN if an identifier uses Other_ID_Start or
Other_ID_Continue
type: behavior
versions: Python 3.4
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<http://bugs.python.org/issue24194>
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