Tim Peters added the comment: > random() may return 1.0 exactly
That shouldn't be possible. Although the code does assume C doubles have at least 53 bits of mantissa precision (in which case it does arithmetic that's exact in at least 53 bits - cannot round up to 1.0; but _could_ round up if the platform C double has less than 53 bits of precision). > py> x = 0.9999999999999999 > py> for i in range(1, 1000000): > ... if int(i*x) == i: > ... print i > ... break > ... > 2049 Very surprising! Which platform & Python is that? The loop runs to completion on my box: Python 2.7.9 (default, Dec 10 2014, 12:28:03) [MSC v.1500 64 bit (AMD64)] on win32 ---------- nosy: +tim.peters _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue24546> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
