New submission from Antoine Pietri: In the new types.coroutines() documentation, it is not clearly stated whether this function is idempotent or not: what happens when it is called on a function that is already a native coroutine?
---------- assignee: docs@python components: Documentation messages: 247184 nosy: docs@python, seirl priority: normal severity: normal status: open title: types.coroutines() idempotence documentation versions: Python 3.5 _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue24692> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
