Eric V. Smith added the comment: Yes, Jelle, you are correct in all 3 cases. Remember that the steps are to extract the string from the source code, decode backslash escapes, and only then treat it as an f-string.
For the first case, without the 'f' prefix: '{ {1: 2\N{RIGHT CURLY BRACKET}[1]}' == '{ {1: 2}[1]}' Then, applying the 'f': f'{ {1: 2}[1]}' == '2'. For the last 2, since they're syntax errors without the 'f', they're also syntax errors with the 'f'. I'll have a new version, with tests for all of these cases, posted in the next few hours. You can leverage the tests. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue24965> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com