Antti Haapala added the comment:
super() without arguments gives proper "super() without arguments" in
functions, generator functions nested in methods, if *those* do not have
arguments. But if you use super() in a nested function that takes an argument,
or in a generator expression or a comprehension, you'd get
Got exception: TypeError super(type, obj): obj must be an instance or
subtype of type
which is really annoying. Furthermore, if a nested function took another
instance of type(self) as the first argument, then super() could refer
unexpectedly to wrong instance:
class Bar(Foo):
def calculate(self, other_foos):
def complicated_calculation(other):
super().some_method(other)
for item in other_foos:
complicated_calculation(item)
now the `super()` call would not have implied `self` of `calculate` as the
first argument, but the `other` argument of the nested function, all without
warnings.
I believe it is a mistake that these nested functions can see `__class__` at
all, since it would just mostly lead them misbehaving unexpectedly.
----------
components: +Interpreter Core
title: super() does not work nested -> super() does not work in nested
functions, genexps, listcomps, and gives misleading exceptions
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Python tracker <[email protected]>
<http://bugs.python.org/issue26495>
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