Steven D'Aprano added the comment:
To explain in more detail: ``type('s').startswith`` is the same as
``str.startswith``, which is an unbound method in Python 2 and a regular
function in Python 3. Either way, it expects *two* arguments: a string which
becomes "self", and a second string argument, which is the prefix being tested
for.
So type('any string').startswith('alphabet', 'al') is a long way of writing
'alphabet'.startswith('al').
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nosy: +steven.daprano
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<http://bugs.python.org/issue27017>
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