Eryk Sun added the comment:
What you're looking for is in the 2nd paragraph of the ast docs:
An abstract syntax tree can be generated by passing
ast.PyCF_ONLY_AST as a flag to the compile() built-in
function, or using the parse() helper provided in this
module. The result will be a tree of objects whose
classes all inherit from ast.AST. An abstract syntax
tree can be compiled into a Python code object using
the built-in compile() function.
For example:
>>> mod = compile('42', '', 'exec', ast.PyCF_ONLY_AST)
>>> mod
<_ast.Module object at 0x7f0e45b15be0
>>> ast.dump(mod)
'Module(body=[Expr(value=Num(n=42))])'
In the discussion of `flags`, I think the compile docs should explicitly list
ast.PyCF_ONLY_AST and the CO_FUTURE_* flags in a table.
----------
nosy: +eryksun
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue27119>
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