STINNER Victor added the comment:
"Right now the way to work around this is to get some deterministic hash from
your string; one mechanism being a truncated SHA256 hash, ..."
It looks like I missed something. Lib/random.py already computes the SHA-512
hash of you pass a string to random.Random constructor?
Using a string as a seed for random.Random already works as expected in Python
3.6:
haypo@selma$ python3 -c "import random; r=random.Random('abc');
print(''.join(map(str, (r.randrange(10) for x in range(10)))), hash('abc'))"
8755240310 6396067846301608395
haypo@selma$ python3 -c "import random; r=random.Random('abc');
print(''.join(map(str, (r.randrange(10) for x in range(10)))), hash('abc'))"
8755240310 -1771227904188177035
haypo@selma$ python3 -c "import random; r=random.Random('abc');
print(''.join(map(str, (r.randrange(10) for x in range(10)))), hash('abc'))"
8755240310 1726464324144904308
haypo@selma$ python3 -c "import random; r=random.Random('abc');
print(''.join(map(str, (r.randrange(10) for x in range(10)))), hash('abc'))"
8755240310 2069899884777593571
haypo@selma$ python3 -c "import random; r=random.Random('abc');
print(''.join(map(str, (r.randrange(10) for x in range(10)))), hash('abc'))"
8755240310 -8244933646981095152
haypo@selma$ python3 -c "import random; r=random.Random('abc');
print(''.join(map(str, (r.randrange(10) for x in range(10)))), hash('abc'))"
8755240310 -3269879388324739111
It was already the case in Python 2.7.
----------
nosy: +haypo
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<http://bugs.python.org/issue27706>
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