Julien Palard added the comment:
I renamed your function groupby2 to compare it with itertools.groupby and
tested but:
>>> print(list(groupby2(['A', 'B'])))
does not returns, looks like your implementation have a bug, so I tried:
>>> for k in groupby2(['A', 'B']):
... print(k)
and I'm getting loads of:
('A', <generator object groupby2._group at 0x7f0476809f10>)
('A', <generator object groupby2._group at 0x7f0476851f68>)
('A', <generator object groupby2._group at 0x7f0476809f10>)
('A', <generator object groupby2._group at 0x7f0476851f68>)
('A', <generator object groupby2._group at 0x7f0476809f10>)
('A', <generator object groupby2._group at 0x7f0476851f68>)
('A', <generator object groupby2._group at 0x7f0476809f10>)
('A', <generator object groupby2._group at 0x7f0476851f68>)
('A', <generator object groupby2._group at 0x7f0476809f10>)
('A', <generator object groupby2._group at 0x7f0476851f68>)
You may also want to test your implementation against
https://github.com/python/cpython/blob/master/Lib/test/test_itertools.py#L699
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nosy: +mdk
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<http://bugs.python.org/issue28939>
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