New submission from lanf0n: test code below:
```python >>> from types import MethodType >>> class A: ... def f(self): ... print(__class__) ... >>> a = A() >>> a.fn = MethodType(lambda s: print(__class__), a) >>> >>> a.f() <class '__main__.A'> >>> a.fn() Traceback (most recent call last): File "<stdin>", line 1, in <module> File "<stdin>", line 1, in <lambda> NameError: name '__class__' is not defined ``` this behavior affect `super()` not work in patched function scope, of course we can use old super as super(self.__class__, self) to make it work as expected, but I think it should work as original method if we already bounded the function to instance(class). ---------- components: Library (Lib) messages: 284313 nosy: lanfon72 priority: normal severity: normal status: open title: __class__ not exists in the method which bounded by types.MethodType. type: behavior versions: Python 3.5, Python 3.6 _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue29114> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
