Serhiy Storchaka added the comment: I don't think it should. You can use operator.add() if you need to fall back to a __radd__ of the right operand.
operator.concat() is Python API to the sq_concat slot. It falls back to __add__() just because instances of user classes defining an __add__() method only have an nb_add slot, not an sq_concat slot. Third-party classes (maybe NumPy arrays, I don't know) can have different implementations of sq_concat and nb_add. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue29139> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
