Serhiy Storchaka added the comment: There is no such need. You can use operators.
any(arg1, arg2, arg3) -> arg1 or arg2 or arg3 all(arg1, arg2, arg3) -> arg1 and arg2 and arg3 sum(arg1, arg2, arg3) -> arg1 + arg2 + arg3 ---------- nosy: +serhiy.storchaka resolution: -> rejected stage: -> resolved status: open -> closed _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue29433> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
