Mark Dickinson <[EMAIL PROTECTED]> added the comment: A cheap trick would be to use the identity
expm1(x) = 2*exp(x/2)*sinh(x/2) This could also be used in Python as a workaround, for now. But I agree that expm1 should go into the math library. _______________________________________ Python tracker <[EMAIL PROTECTED]> <http://bugs.python.org/issue3501> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
