New submission from bo qu: if "[" is the first char in a string, then re.match can't match any pattern from the string, but re.findall works fine
details as follows: [da@namenode log]$ python3 Python 3.4.3 (default, Jun 14 2015, 14:23:40) [GCC 4.4.7 20120313 (Red Hat 4.4.7-11)] on linux Type "help", "copyright", "credits" or "license" for more information. >>> import re >>> cyzd="[abc]" >>> cyzd '[abc]' >>> pattern="ab(.*)" >>> pattern 'ab(.*)' >>> match=re.match(pattern, cyzd) >>> match >>> pattern=r'ab(.*)' >>> re.findall(pattern, cyzd) ['c]'] ---------- components: Regular Expressions messages: 290968 nosy: bo qu, ezio.melotti, mrabarnett priority: normal severity: normal status: open title: re.match failed to match left square brackets as the first char type: behavior versions: Python 3.5 _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue29959> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com