Serhiy Storchaka added the comment:
re.escape() shouldn't be used for a replacement template. You need just double
backslashes when escape a literal string for a replacement template:
s.replace('\\', '\\\\'). This should be documented if still is not documented.
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nosy: +serhiy.storchaka
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue30133>
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