Martin Panter added the comment:
>>> f"{number:#0x}" # using integer format specifier
It’s not clear what your purpose was adding the above line, but the zero flag
(0) does nothing because there is no “width” field. I think it could be
misleading, because it is actually the “#x” codes that generate the “0x” prefix.
If you want to illustrate a minimum width, I suggest something like
>>> f"{number:#06x}"
'0x0400'
or (if the number is never negative)
>>> f"0x{number:04X}"
'0x0400'
Or if you don’t care about the width:
>>> f"{number:#x}"
'0x400'
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nosy: +martin.panter
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue31487>
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