Serhiy Storchaka <[email protected]> added the comment:
I think the break in the loop for [.='text'] is not correct.
>>> from xml.etree import ElementTree as ET
>>> e =
>>> ET.XML('<root><a><b>text</b></a><a><b></b></a><a><b>text</b></a></root>')
>>> list(e.findall('.//a[b="text"]'))
[<Element 'a' at 0x7ffadb305d58>, <Element 'a' at 0x7ffadb305f58>]
>>> list(e.findall('.//a[.="text"]'))
[<Element 'a' at 0x7ffadb305d58>]
I expect that findall() finds all matched elements, not just the first one.
Both above requests should return the same result.
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Python tracker <[email protected]>
<https://bugs.python.org/issue31648>
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