Romuald Brunet <[email protected]> added the comment:
My use case:
try:
s = SMTP('myhost')
s.do_some_sending()
finaly:
if s is not None and s.sock is not None:
s.quit()
But I realize just now that in that case, if s was initialized correctly, its
sock was inevitably set
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<https://bugs.python.org/issue32680>
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