New submission from Thomas Kriechbaumer <kriechbau...@gmail.com>: ipaddress.IPv4Address and ipaddress.IPv6Address provide a is_private function that indicates if the address (or network) is part of a "private" IP range, as designated by the IANA special-use registry.
The current documentation is as follows: > is_private > True if the address is allocated for private networks. See > iana-ipv4-special-registry (for IPv4) or iana-ipv6-special-registry (for > IPv6). However, IPv4-mapped IPv6 addresses are currently being reported as "private" by this function (see https://github.com/python/cpython/commit/22c31764262b02338265a059c738b8d24fd9a0e4#diff-0fc57874e463b95dbdfe6f80ae918ea1R1869). I consider this a bug or at least counter-intuitive, because e.g. ::ffff:8.8.8.8 is most definitely NOT a private IP address, and yet the ipaddress.is_private function reports True. The IANA special-use registry does not contain any references to "being private" for the ::ffff region. It just designates it to be used for IPv4-mapped address. ---------- components: Library (Lib) messages: 316213 nosy: Thomas Kriechbaumer priority: normal severity: normal status: open title: ipaddress is_private misleading for IPv4 mapped IPv6 addresses versions: Python 3.4, Python 3.5, Python 3.6, Python 3.7, Python 3.8 _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue33433> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
