New submission from Salomon <[email protected]>:
I am seeing an issue when attempting to use default kwargs in decorated
functions.
I would post reproduction steps, but instead I have written a snippet which
should showcase the issue.
Snippet:
```python
def decorator():
def inner(f):
def wrapper(*args, **kwargs):
# Zoinks, Scoob!
print('Decorator: {}'.format(''.join(kwargs.values())))
print(f(*args, **kwargs))
return wrapper
return inner
@decorator()
def func(foo='wont print in the decorator'):
return 'Func: {}'.format(foo)```
The following calls to 'func' should show you what Im talking about clearly:
```
func()
-> Decorator:
-> Func: wont print in the decorator
func(foo='will print in the decorator')
-> Decorator: will print in the decorator
-> Func: will print in the decorator
```
I would expect, though correct me if I am wrong, that both of these calls
should print in the decorator and the function call.
For convenience, some REPL.it links:
3.6.1 -> https://repl.it/@SalomonSmeke/Python3-Decorator-Bug
2.7.10 -> https://repl.it/@SalomonSmeke/Python-Decorator-Bug
Using @wrap from functools:
2.7.10 -> https://repl.it/@SalomonSmeke/Python-Decorator-Bug-using-FuncTools
Thank you for your time.
P.S.
This is my first issue submitted to Python, please let me know if there is
detail lacking. Im happy to provide what I can.
----------
messages: 318892
nosy: ssmeke
priority: normal
severity: normal
status: open
title: Decorated (inner/wrapped) function kwarg defaults dont pass through
decorator.
type: behavior
versions: Python 2.7, Python 3.4, Python 3.5, Python 3.6
_______________________________________
Python tracker <[email protected]>
<https://bugs.python.org/issue33790>
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