Dong-hee Na <donghee.n...@gmail.com> added the comment:
Thanks,
my easy patch is worked by pre-checking left paren index. but some edge case
which I don't expect should be considered.
if (left_paren_index != -1) {
- /* Use default error message for any line with an opening paren */
- return 0;
+ int found_white_space = 0;
+ int found_other_char = 0;
+ Py_ssize_t pos = 0;
+ while(pos != left_paren_index) {
+ int kind = PyUnicode_KIND(self->text);
+ void *data = PyUnicode_DATA(self->text);
+ Py_UCS4 ch = PyUnicode_READ(kind, data, pos);
+ if (Py_UNICODE_ISSPACE(ch)) {
+ found_white_space = 1;
+ }
+ if (!Py_UNICODE_ISSPACE(ch) && found_white_space == 1) {
+ found_other_char = 1;
+ }
+ pos++;
+ }
+
+ if (found_other_char == 0) {
+ return 0;
+ }
}
Type "help", "copyright", "credits" or "license" for more information.
>>> print (foo.)
File "<stdin>", line 1
print (foo.)
^
SyntaxError: invalid syntax
>>> print "a".toupper().tolower()
File "<stdin>", line 1
print "a".toupper().tolower()
^
SyntaxError: Missing parentheses in call to 'print'. Did you mean
print("a".toupper().tolower())?
SyntaxError: Missing parentheses in call to 'print'. Did you mean
print(Foo().header(a=foo(1)))?
----------
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<https://bugs.python.org/issue34013>
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