New submission from Clint Hepner <[email protected]>:
I expected to be able to pass None as an explicit count to itertools.repeat to
get the default behavior of an infinite iterator:
>>> list(islice(repeat(1), 10))
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
>>> list(islice(repeat(1, None), 10))
Traceback (most recent call last):
File "<stdin>", line 1 in <module>
TypeError: 'NoneType' object cannot be interpreted as an integer
----------
components: Library (Lib)
messages: 322010
nosy: chepner
priority: normal
severity: normal
status: open
title: itertools.repeat does not accept None as an explicit count
versions: Python 3.7
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Python tracker <[email protected]>
<https://bugs.python.org/issue34169>
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