New submission from Clint Hepner <clint.hep...@gmail.com>:

I expected to be able to pass None as an explicit count to itertools.repeat to 
get the default behavior of an infinite iterator:

    >>> list(islice(repeat(1), 10))
    [1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
    >>> list(islice(repeat(1, None), 10))
    Traceback (most recent call last):
      File "<stdin>", line 1 in <module>
    TypeError: 'NoneType' object cannot be interpreted as an integer

----------
components: Library (Lib)
messages: 322010
nosy: chepner
priority: normal
severity: normal
status: open
title: itertools.repeat does not accept None as an explicit count
versions: Python 3.7

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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue34169>
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