New submission from mkurnikov <maxim.kurni...@gmail.com>:
Suppose I have two dataclasses: @dataclass class NestedDataclass(object): name: str options: Dict[str, Any] = field(default_factory=dict) @dataclass class RootDataclass(object): nested_list: List[NestedDataclass] I want a dict under the key "options" to be merged in the NestedDataclass dict in the dataclasses.asdict(root_dcls_instance). For that, according to docs, I need to specify dict_factory= for dataclasses.asdict() function. The problem is that, according to the implementation, when this function "meets" dataclass, there's no way to customize how result dict will be built. Dataclass itself is never passed to the function. if _is_dataclass_instance(obj): result = [] for f in fields(obj): value = _asdict_inner(getattr(obj, f.name), dict_factory) result.append((f.name, value)) return dict_factory(result) Yes, I can catch "result" obj (what I did in the end): def root_dataclass_dict_factory(obj): if isinstance(obj, list): dataclass_dict = dict(obj) if 'options' in dataclass_dict: dataclass_dict.update(dataclass_dict.pop('options')) return dict(obj) The problem is that type of the dataclass is lost for the list, and if by any chance later I'll have "options" key in the RootDataclass, there's no way for me to distinguish between them cleanly. Other solution is to iterate over the RootDataclass dictionary, follow the path to the NestedDataclass and change dictionary there, but it even uglier. Would be nice to be able to somehow hook into the field traversal of the dataclass instance. ---------- components: Library (Lib) messages: 323542 nosy: mkurnikov priority: normal severity: normal status: open title: Add a way to customize iteration over fields in asdict() for the nested dataclasses type: enhancement versions: Python 3.6 _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue34409> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com