Jeroen Demeyer <j.deme...@ugent.be> added the comment:
> And one more:
x = (x * mult) ^ t;
also appears to work equally well.
The order of operations does not really matter: you can write the loop as
x *= mult # Appears only in FNV-1
x ^= t[0]
x *= mult
x ^= t[1]
x *= mult
x ^= t[2]
x *= mult
x ^= t[3]
x *= mult # Appears only in FNV-1a
The initial multiplication is equivalent to changing the initial value and the
final multiplication is just a permutation of the outputs. None of those should
really affect the quality of the hash.
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue34751>
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