Jeroen Demeyer <j.deme...@ugent.be> added the comment:
> And one more: x = (x * mult) ^ t; also appears to work equally well. The order of operations does not really matter: you can write the loop as x *= mult # Appears only in FNV-1 x ^= t[0] x *= mult x ^= t[1] x *= mult x ^= t[2] x *= mult x ^= t[3] x *= mult # Appears only in FNV-1a The initial multiplication is equivalent to changing the initial value and the final multiplication is just a permutation of the outputs. None of those should really affect the quality of the hash. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue34751> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com