New submission from metaxm <met...@gmail.com>:
>>> def f(a, b, c): ... pass >>> f(a=1, 2, 3) SyntaxError: positional argument follows keyword argument >>> f(a=1, *(2, 3)) TypeError: f() got multiple values for argument 'a' f(a=1, 2, 3) will cause a SyntaxError, but f(a=1, *(2, 3)) will cause a TypeError. This makes me feel confused. As keyword arguments must follow positional arguments, I suppose a SyntaxError rather than a TypeError should be reported if a variadic argument follows keyword arguments. Would you kindly explain why the CPython takes different actions for these two cases? ---------- components: Interpreter Core messages: 326945 nosy: metaxm priority: normal severity: normal status: open title: f(a=1, *args) should be a SyntaxError type: behavior versions: Python 3.6, Python 3.7, Python 3.8 _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue34882> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
