New submission from Gyff Mjord <[email protected]>:
Because of [reasons], I installed a FreeBSD and recompiled it to provide a
minimalist kernel. Thus, it does not have the entropy devices /dev/urandom and
/dev/random
It is a FreeBSD-10-0 running in a Hyper-V virutalization platform.
I kinda recompiled python-3.7.1 from the source code to get my own version of
python running, but I got stuck in this part. So looking at the
Modules/bootstrap_hash.c file I do not see the code of pyurandom() falling back
to a something silly.
Plus, there is a problem that happens only in Unix at least in this version of
python. Looking at the code of the same file. we can see:
static int pyurandom(...)
{
...
int res
...
if (res < 0){
return -1
}
if (res == 1){
return 0
}
...
}
I am sorry for the laziness but I believe my point is clear.
The thing is. If the random function returns 0 it will return 0 but if it
returns 1 it will also return 0.
In other words, the number 1 is out of the scope of the random numbers. It is a
small prejudice for the random function, but it is not mathematically right.
This issue with the number 1, does not happen if the user does not have
/dev/random (But it still needs /dev/urandom)
----------
components: FreeBSD
messages: 329005
nosy: koobs, pehdrah
priority: normal
severity: normal
status: open
title: pyurandom() fails if user does not have an entropy device
type: behavior
versions: Python 3.7
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Python tracker <[email protected]>
<https://bugs.python.org/issue35127>
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