STINNER Victor <vstin...@redhat.com> added the comment:
Python 3.6 no longer accept bugfixes, only security fixes: http://devguide.python.org/#status-of-python-branches You can try faulthandler has a workaround. For example, install faulthandler signal handler using faulthandler.register(signal.SIGUSR1) and then send a SIGUSR1 signal to the blocked process. You might want to write the output into a file if you don't have access the program stdout: use the 'file' parameter of faulthandler.register(). See also faulthandler.dump_traceback_later() to use a timeout. https://docs.python.org/dev/library/faulthandler.html ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue35132> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
