Karthikeyan Singaravelan <[email protected]> added the comment:
Agreed with @remi.lapeyre. There is no delayed evaluation in Python and this is
not only related to print but it's the general evaluation model in Python.
Another example as below since foo(1) is used as an argument it's evaluated
first and then the return value is passed.
def bar(a, b):
print("bar ", a, b)
return (a, b)
def foo(b):
print("foo ", b)
return b
bar(foo(1), 2) # foo is first evaluated to pass 1 bar
$ python3 /tmp/foo.py
foo 1
bar 1 2
Closing this as not a bug.
----------
nosy: +xtreak
resolution: -> not a bug
stage: -> resolved
status: open -> closed
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Python tracker <[email protected]>
<https://bugs.python.org/issue36223>
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