Martin v. Löwis <mar...@v.loewis.de> added the comment:
Correct me if I'm wrong, but I think computing the quotient is not
necessary; the remainder is sufficient:
def round(n, i):
if i >= 0: return n
i = 10**(-i)
r = n%(2*i)
if r < i:
return n-r
return n-r+2*i
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue4707>
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