Steven D'Aprano <steve+pyt...@pearwood.info> added the comment:

Why would they give the same result when the code is different?

    #1 assign c, d, e and everything left over goes into b
    *b, c, d, e, = [1, 2, 3, 4]

    #2 assign c, d and everything left over goes into b
    *b, c, d, = [1, 2, 3, 4]

    #3 assign c and everything left over goes into b
    *b, c, = [1, 2, 3, 4]

    #4 assign nothing and everything left over goes into b
    *b, = [1, 2, 3, 4]

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nosy: +steven.daprano

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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue38516>
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