Matthew Barnett <[email protected]> added the comment:
It's been many years since I looked at the code, and there have been changes
since then, so some of the details might not be correct.
As to have it should behave:
re.match('(?:()|(?(1)()|z)){1,2}(?(2)a|z)', 'a')
Iteration 1.
Match the repeated part. Group 1 matches.
Iteration 2.
Match the repeated part. Group 1 matches.
Has group 2 matched? No.
Try to match 'z'. Fail and backtrack.
Retry the repeated part.
Iteration 2.
Has group 1 matched? Yes.
Group 2 matches.
Has group 2 matched? Yes.
Try to match 'a'. Success. Group 1 matched and group 2 matched.
re.match('(?:()|(?(1)()|z)){1,2}(?(1)a|z)', 'a')
Iteration 1.
Match the repeated part. Group 1 matches.
Iteration 2.
Match the repeated part. Group 1 matches.
Has group 1 matched? Yes.
Try to match 'a'. Success. Group 1 matched and group 2 didn't match.
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<https://bugs.python.org/issue23692>
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