Wolfgang Stöcher <wolfg...@stoecher.com> added the comment:
In symtable.Function.get_locals() symbols with scopes in (LOCAL, CELL) are
selected. Also
>>> code = """\
... def foo():
... x = 42
... def bar():
... return x
... """
>>> import symtable
>>> top = symtable.symtable(code, "?", "exec")
>>> top.get_children()[0].lookup('x')._Symbol__scope == symtable.CELL
True
So I guess this would be the correct fix then:
def is_local(self):
return self.__scope in (LOCAL, CELL)
----------
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue40196>
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