Eric V. Smith <e...@trueblade.com> added the comment:
This isn't doing what you think. Because you throw away the object after computing its id, the same memory is reused and you get the same id. Consider: >>> a = [1,2,3] >>> b = [3,4,5] >>> id(a[:]) == id(b[:]) True There's no problem here, but it does show that you need to be careful with "is" and "id". ---------- nosy: +eric.smith resolution: -> not a bug stage: -> resolved status: open -> closed _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue40565> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
