Christian Heimes <li...@cheimes.de> added the comment:
There is no need to add a new flag to quote. You can easily archive your goal
with a simple regular expression substitution:
>>> import re, urllib.parse
>>> s = urllib.parse.quote("Example|#?")
>>> s
'Example%7C%23%3F'
>>> re.sub("%[0-9A-F]{2}", lambda q: q.group(0).lower(), s)
'Example%7c%23%3f'
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue40426>
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