Raymond Hettinger <raymond.hettin...@gmail.com> added the comment:
The next() function has a different signature than the __next__() method. The
former takes one or two arguments. That latter only takes one.
>>> it = iter('abcde')
>>> next(it)
'a'
>>> next(it, 'default')
'b'
>>> it.__next__()
'c'
>>> it.__next__('default')
Traceback (most recent call last):
File "<pyshell#4>", line 1, in <module>
it.__next__('default')
TypeError: expected 0 arguments, got 1
----------
nosy: +rhettinger
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue40579>
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