Tim Peters <t...@python.org> added the comment:
I don't want something probabilistic. Fix it or don't ;-) One thing that would work, but at the cost of non-determinism: do the same as now, but obtain the number part of the group name by applying next() to a module-global private instance of itertools.count(). That will keep the numbers increasing "forever", and across calls. The point to using .count() is that it's atomic (i.e., won't repeat a number if multiple threads happen to be constructing regexps simultaneously). It's a darned silly amount of effort, though ;-) ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue40480> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
