Pablo Galindo Salgado <pablog...@gmail.com> added the comment:
>But then why I still can access this variable? Shouldn't it then be resulting in NameError as it's undefined variable at this point of time? I don't think so, this is the same as if you do: def f(exc): del exc return exc >>> f(3) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "lel.py", line 3, in f return exc UnboundLocalError: local variable 'exc' referenced before assignment ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue40728> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com