Rémi Lapeyre <remi.lape...@henki.fr> added the comment:
I've looked into this, in Bdb both the part where the code is compiled and the
one where the code is run are in the run() method
(https://github.com/python/cpython/blob/master/Lib/bdb.py#L565-L585):
def run(self, cmd, globals=None, locals=None):
"""Debug a statement executed via the exec() function.
globals defaults to __main__.dict; locals defaults to globals.
"""
if globals is None:
import __main__
globals = __main__.__dict__
if locals is None:
locals = globals
self.reset()
if isinstance(cmd, str):
cmd = compile(cmd, "<string>", "exec")
sys.settrace(self.trace_dispatch)
try:
exec(cmd, globals, locals)
except BdbQuit:
pass
finally:
self.quitting = True
sys.settrace(None)
This is an issue as SyntaxError may come from two lines
- the call to compile() which means the code being run is not valid Python, in
this case the current behaviour of PDB to exit is correct as there is nothing
to debug
- the call to exec() in which case a SyntaxError can happen like in the
report, and PDB should go in post mortem debug mode.
One way to fix the issue would be to catch the error in compile() and wrap it
in a BdbSyntaxError so that PDB can differentiate between the two, another to
keep BDB as it is and change PDB so that it compiles the code first, and call
run() in a second step. I think the last one is better and will start writing a
PR for this.
----------
nosy: +remi.lapeyre
versions: +Python 3.10, Python 3.7, Python 3.9
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<https://bugs.python.org/issue40403>
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