Ezio Melotti <ezio.melo...@gmail.com> added the comment: itertools.permutations_with_repetitions(iterable[, r]) is not necessary, writing in the doc that set(itertools.permutations(iterable[, r])) has the same result is probably enough (I put the set() in the wrong place in the previous message - this version is also less efficient because it has to generate duplicate elements that will be removed by set()). I suggested to include math.npermutations_with_repetitions for completeness, even if it's not widely used IMHO is not coherent to have formulas to calculate combinations with and without repetitions and a just a formula for permutations without repetitions.
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