Mark Shannon <m...@hotpy.org> added the comment:
The following code is completely eliminated by the macros. 1. if 0: 2. secret_debugging_code() PEP 626 says that all executed lines of code must generate trace events, so we need to emit an instruction for line 1. Dead code elimination will remove the `secret_debugging_code()`, but leave the test. The peephole optimiser can then reduce it to a NOP, but won't eliminate it as it is the only instruction for line 1. ---------- stage: patch review -> _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue42246> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
